SOLUTION: Find the slope-intercept form of the equation of the line that passes through (2, −1) and is parallel to 8x + 3y = 9.

Algebra ->  Linear-equations -> SOLUTION: Find the slope-intercept form of the equation of the line that passes through (2, −1) and is parallel to 8x + 3y = 9.      Log On


   



Question 1196327: Find the slope-intercept form of the equation of the line that
passes through (2, −1) and is parallel to 8x + 3y = 9.

Found 3 solutions by MathLover1, MathTherapy, josgarithmetic:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the slope-intercept form of the equation of the line;
y-y%5B1%5D=m%28x-x%5B1%5D%29
passes through (2, -1)
perpendicular to 8x+%2B+3y+=+9

first find the slope of given line
8x+%2B+3y+=+9
++3y+=+-8x%2B9
++y+=+-%288%2F3%29x%2B9%2F3
++y+=+-%288%2F3%29x%2B3
so, a slope is m=-%288%2F3%29

recall that parallel lines have same slopes, so the slope of the line perpendicular to given line will be
m=-%288%2F3%29

now use given point and a slope to find equation
y-y%5B1%5D=m%28x-x%5B1%5D%29..........plug in the coordinates of the point (2, -1) and the slope m=-%288%2F3%29

y-%28-1%29=-%288%2F3%29%28x-2%29
y%2B1=-%288%2F3%29%28x-2%29
y%2B1=-%288%2F3%29x-%28-%288%2F3%29%292
y%2B1=-%288%2F3%29x%2B16%2F3
y=-%288%2F3%29x%2B16%2F3-1
y=-%288%2F3%29x%2B13%2F3=> your line









Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope-intercept form of the equation of the line that
passes through (2, −1) and is parallel to 8x + 3y = 9.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
PARALLEL, then the left-side stays the same.

8x%2B3y=8%2A2%2B3%28-1%29
-
3y=16-3-8x
3y=-8x%2B13
highlight%28y=-%288%2F3%29x%2B13%2F3%29-------------now in slope-intercept form.