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Question 1189526: How many different counting numbers will each leave a remainder of 5 when divided into 47?
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! won't be anything under 5 or 5.
6 works (42 is 47-5)
7 works (same)
try their multiples
12 doesn't work
14 does work
21 works
The answer is 4.
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
If a number divided into 47 leaves remainder 5, then
(1) it is 6 or greater; and
(2) it leaves remainder 0 when divided into 47-5=42.
So the numbers that leave remainder 5 when divided into 42 are the factors of 42 that are 6 or larger.
Factors of 42:
1, 42
2, 21
3, 14
6, 7
Factors of 42 that are 6 or greater: 6, 7, 14, 21, 42
ANSWER: 5
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