SOLUTION: A man leaves his work at 5:30 PM and heads toward home which is 5 km away. He walks at 5 km per hour until he receives a call from his wife. She misses him and wants to see him as

Algebra ->  Linear-equations -> SOLUTION: A man leaves his work at 5:30 PM and heads toward home which is 5 km away. He walks at 5 km per hour until he receives a call from his wife. She misses him and wants to see him as       Log On


   

Question 1187710: A man leaves his work at 5:30 PM and heads toward home which is 5 km away. He walks at 5 km per hour until he receives a call from his wife. She misses him and wants to see him as soon as possible. He runs the rest of the way at 12 km per hour and arrives home at 6:09 PM
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Total time is 39 minutes or 0.65 hours.
Let x be the regular expected time if he would have used his regular speed for the whole trip. 
                 SPEEDS              TIMES        DISTANCE

regular speed        5                 x           5x

running             12               0.65-x        12(0.65-x)

total                                  0.65          5

highlight_green%285x%2B12%280.65-x%29=5%29

Just study and understand the setup, and solve the equation. You can then answer your two questions.