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Question 1185422: How do I find the distance between and enter it as a radical or a decimal?
(-5,3) and (5,-3)
Found 2 solutions by josgarithmetic, Theo:
Answer by josgarithmetic(39617)   (Show Source):
Answer by Theo(13342)  (Show Source):
You can put this solution on YOUR website! the distance between (-5,3) and (5,-3) would be found by using the formula of:
length of a two dimensional line on a graph = square root of ((y2-y1)^2 + (x2-x1)^2)
you assing (x1,y1) to one of the points and (x2,y2) to the other point.
it doesn't matter which is assigned to which.
the length would be the same.
for example:
let(x1,y1) = (-5,3) and let (x2,y2) = (5,-3).
the length is equal to sqrt((x2-x1)^2 + (y2-y1)^2) = sqrt(5--5)^2 + (-3-3)^2) = sqrt(10^2 + (-6)^2) = sqrt(100 + 36) = sqrt(136).
let (x1,y1) = (5,-3) and let (x2,y2) = (-5,3).
the length is equal to sqrt((x2-x1)^2 + (y2-y1)^2) = sqrt(-5-5)^2 + (3--3)^2) = sqrt((-10)^2 + 6^2) = sqrt(100 + 36) = sqrt(136).
sqrt means the square root of.
if you look at the line on a graph, it would look like this.
the line itself is the hypotenuse of the right triangle formed.
the vertical leg is the length of (y2 - y1).
the horizontal leg is the length of (x2 - x1).
the pythagorean formula is used to get the length of the line itself.
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