SOLUTION: Find the equation of the line through point (−5,5) and perpendicular to y=59x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).and the next problem is Find the
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-> SOLUTION: Find the equation of the line through point (−5,5) and perpendicular to y=59x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).and the next problem is Find the
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Question 1183225: Find the equation of the line through point (−5,5) and perpendicular to y=59x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).and the next problem is Find the equation of the line through point (−1,2) and perpendicular to x+3y=3. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12). Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! -----
equation of the line through point (−5,5) and perpendicular to y=59x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).and
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Negative reciprocal of coefficient on x term, because asked for "perpendicular" line.
You can put this solution on YOUR website! Find the equation of the line through point (−5,5) and perpendicular to y=59x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).and the next problem is Find the equation of the line through point (−1,2) and perpendicular to x+3y=3. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).
. He's WRONG, so: ------ Switching coordinates, negating NEW y coordinate, and equating to a constant,
calculated using the coordinates of the requested equation
Same concept applies to the 2nd equation that's being sought.