SOLUTION: Maximum height: If a soccer ball is kicked straight up from the ground with an initial velocity of 32 feet per second, then its height above the earth in feet is given by s(t)=-16

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Question 118252This question is from textbook Elementary and Intermediate Algebra
: Maximum height:
If a soccer ball is kicked straight up from the ground with an initial velocity of 32 feet per second, then its height above the earth in feet is given by s(t)=-16t2 + 32t where t is time in seconds. Graph this parabola for 0-
This question is from textbook Elementary and Intermediate Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If a soccer ball is kicked straight up from the ground with an initial velocity of 32 feet per second, then its height above the earth in feet is given by s(t)=-16t2 + 32t where t is time in seconds. Graph this parabola for 0- ------------------------
Maximum occurs when t = -b/2a = -32/(2*-16) = 1 second
The height when t = 1 second is s(1) = -16(1^2)+32(t) = 16 ft.
Plot the point (1,16)
The y-intercept occurs when t=0; s(0) = 0
Plot the point (0,0).
Draw a parabola through those two points an opening downward
because of the negative on -16t^2
-------------
Graph:
graph%28400%2C300%2C-5%2C5%2C-5%2C20%2C-16x%5E2%2B32x%29
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Cheers,
stan H.