SOLUTION: Graph the following equation. y=1/3x+1

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Question 118022: Graph the following equation.
y=1/3x+1
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=%281%2F3%29%2Ax%2B1 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-9

y=%281%2F3%29%2A%28-9%29%2B1

y=-9%2F3%2B1 Multiply

y=-6%2F3 Add

y=-2 Reduce

So here's one point (-9,-2)




Now lets find another point

Plug in x=-6

y=%281%2F3%29%2A%28-6%29%2B1

y=-6%2F3%2B1 Multiply

y=-3%2F3 Add

y=-1 Reduce

So here's another point (-6,-1). Add this to our graph





Now draw a line through these points

So this is the graph of y=%281%2F3%29%2Ax%2B1 through the points (-9,-2) and (-6,-1)


So from the graph we can see that the slope is 1%2F3 (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 3 units to get to the next point) the y-intercept is (0,1)and the x-intercept is (-3,0)


We could graph this equation another way. Since b=1 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,1).


So we have one point (0,1)





Now since the slope is 1%2F3, this means that in order to go from point to point we can use the slope to do so. So starting at (0,1), we can go up 1 units



and to the right 3 units to get to our next point


Now draw a line through those points to graph y=%281%2F3%29%2Ax%2B1


So this is the graph of y=%281%2F3%29%2Ax%2B1 through the points (0,1) and (3,2)