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Question 117980: Find the equation, in standard form, with all integer coefficients, of the line
perpendicular to 3x-6y+9 and passing through (-2,-1)
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x-6y+9 and passing through (-2,-1)
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Where is the equal sign on the line "equation"?
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Cheers,
Stan H.
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! 3x-6y+9=0
-6y=-3x-9
y=-3x/-6-9/-6
y=x/2+3/2 this line has a slope=1/2. (red line)
Therefore a perpendicular line has a slope of -2.
If it passes through (-2,-1) then we have the equation:
-1=-2*-2+b
-1=4+b
b=-1-4
b=-5 for the y intercept of this line:
Thus we have the line equation:
y=-2x-5 (green line)
 (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = x/2 +3/2 and y = -2x -5).
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