SOLUTION: A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 25% and the third contains 70%. They want to use all three solutions to

Algebra ->  Linear-equations -> SOLUTION: A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 25% and the third contains 70%. They want to use all three solutions to      Log On


   

Question 1175286: A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 25% and the third contains 70%. They want to use all three solutions to obtain a mixture of 60 liters containing 45% acid, using 2 times as much of the 70% solution as the 25% solution. How many liters of each solution should be used?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
 60 liters 
 45% acid, using 2 times as much of the 70% solution as the 25% solution. 
 .15(60L - 3x)) + .25(x)  + .70(2x) = .45(60L)
 .15(60L) - .45x  + .25(x)  + 1.4x   = .45(60L) 
                                  x = .30(60L)/1.2 = 15L of the 25% solution
 15L of the 25% solution, 30L of the 70% solution & 15L of 15% solution
           27=27 checks
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