SOLUTION: Rate time distance Practice problem Chelsea is 138 miles away from Laura. They are traveling towards each other. If Laura travels 5 mph faster than Chelsea and they meet after

Algebra ->  Linear-equations -> SOLUTION: Rate time distance Practice problem Chelsea is 138 miles away from Laura. They are traveling towards each other. If Laura travels 5 mph faster than Chelsea and they meet after      Log On


   

Question 1175204: Rate time distance Practice problem

Chelsea is 138 miles away from Laura. They are traveling towards each other. If Laura travels 5 mph faster than Chelsea and they meet after 6 hours, how fast was each traveling?


Chelsea is traveling_______mph.




Laura is traveling_________mph.




_______hours at 15 mph




_______hours at 4 mph
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Chelsea's distance traveled + Laura’s distance traveled = 138 miles
t=6+hours
d=rt
let Chelsea's rate be r and Laura’s rate be r%2B5
6%2Ar+%2B+6%2A%28r%2B5%29+=+138
6r+%2B+6r%2B30+=+138
12r=+138-30
12r=+108
r=+108%2F12
r=+9
=>Chelsea was traveling 9%28mil%2Fh%29
then Laura’s rate was r%2B5=9%2B5=14%28mil%2Fh%29