SOLUTION: A store sells televisions for $360 and digital video recorders for $270. At the beginning of the week its entire stock is worth $55,530. During the week it sells three quarters of

Algebra ->  Linear-equations -> SOLUTION: A store sells televisions for $360 and digital video recorders for $270. At the beginning of the week its entire stock is worth $55,530. During the week it sells three quarters of       Log On


   



Question 1173984: A store sells televisions for $360 and digital video recorders for $270. At the beginning of the week its entire stock is worth $55,530. During the week it sells three quarters of the televisions and one third of the digital video recorders for a total of $32,310. How many televisions and digital video recorders did it have in its stock at the beginning of the week?


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


x televisions and y video recorders

The value of the stock at the beginning of the week, at $360 for each television and $270 for each video recorder, was $55,530:

360x%2B270y+=+55530

The sales total for the week, consisting of 3/4 of the televisions and 1/3 of the video recorders, was $32,310:

360%283%2F4%29x%2B270%281%2F3%29y+=+32310
270x%2B90y+=+32310

Multiply the second equation by 3 and subtract the first equation to eliminate y and solve for x. Then use that x value in either original equation to find y.