SOLUTION: f(x)=-2/3(x) + 1/2
Write the equation of a line perpendicular to f that passes through the point (2, 1).
The functions is negative two thirds and the variable is x plus one
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-> SOLUTION: f(x)=-2/3(x) + 1/2
Write the equation of a line perpendicular to f that passes through the point (2, 1).
The functions is negative two thirds and the variable is x plus one
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Question 1173961: f(x)=-2/3(x) + 1/2
Write the equation of a line perpendicular to f that passes through the point (2, 1).
The functions is negative two thirds and the variable is x plus one half.
I'd appreciate a detailed procedure of this because what I really need to do is to is to write a step by step kind of the problem. Answer by math_tutor2020(3817) (Show Source):
This equation is in the form y = mx+b with
m = -2/3 = slope
b = 1/2 = y intercept
We won't use this given y intercept. We'll only use the slope.
The negative reciprocal of the given slope is 3/2. We flip the fraction to go from -2/3 to -3/2. We also flip the sign from negative to positive.
Side note: The original slope -2/3 and the perpendicular slope 3/2 multiply to -1. This works for any pair of perpendicular lines as long as neither line is vertical.
So far we found the perpendicular slope to be m = 3/2
We want this perpendicular line to go through (x,y) = (2,1)
We will use
m = 3/2
x = 2
y = 1
to plug into y = mx+b. Then we'll solve for b
So,
y = mx+b
1 = (3/2)*2+b
1 = 3+b
1-3 = b
-2 = b
b = -2
This means y = mx+b updates to to be the equation of the perpendicular line.
If you wish to use point-slope form, then you could do it like this
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Answer:
Because 3/2 = 1.5, the decimal form of this equation is
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