-2x - 2y = 16 and y = -8
solve by substitution
This is the system of two equations in two unknowns x and y:
Start writing the first equation down,
-2x - 2y = 16
except when you come to "y", don't write "y"; instead write what
"y" equals from the second equation, putting it in parentheses,
which is "(-)". So you write this:
-2x - 2(-8) = 16
Now we replace 2(-8) by the number (-16)
-2x - (-16) = 16
Now we use the definition of subtraction which
tells us that subtracting a negative number isd
adding the opposite positive number:
Next we add -16 to both sides:
-2x + 16 = 16
- 16 -16
-------------
-2x = 0
Now we want to have just x on the left,
so we divide both sides by the coefficient
of x, which is -2
Then we cancel the -2's on the left
which leaves
and do the division of 0 by -2 on the right, getting 0
So 0 is the solution for x.
The solution for the system of equations is (x,y) = (0,-8)
Edwin