SOLUTION: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the apprentice. The second apprentice worked twice as long as the first. If the carpenter and hi

Algebra ->  Linear-equations -> SOLUTION: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the apprentice. The second apprentice worked twice as long as the first. If the carpenter and hi      Log On


   

Question 1168306: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the apprentice. The second apprentice worked twice as long as the first. If the carpenter and his carpenter and his apprentices worked a total of 22 hour, how long did the carpenter work?
1st apprentice = x, 2nd apprentice = 2x, carpenter = 6x
x + 2x + 6x = 22
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
---------------------------------------
he carpenter worked 6 hours longer than the FIRST apprentice. The second apprentice worked twice as long as the first.
------------------------------------- 
Carpenter            6+f
First apprent.        f
Second apprent.       2f
TOTAL                 22

.
.
!