SOLUTION: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the first apprentice. The second apprentice worked twice as long as the first. If the carpenter

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Question 1168293: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the first apprentice. The second apprentice worked twice as long as the first. If the carpenter and his apprentices worked a total of 22 hours, how long did the carpenter work?
Found 3 solutions by mananth, MathTherapy, josgarithmetic:
Answer by mananth(16946) About Me  (Show Source):
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Let Frst apprentice work for x hours
second works 2x hours
Carpenter works for x+6 hours
Total 22 hours
x+2x+x+6 =22
4x+6 = 22
4x =16
divide by 4
x=4
Carpenter works for x+6 hours = 4+6 =10 hours

Answer by MathTherapy(10552) About Me  (Show Source):
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A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the first apprentice. The second apprentice worked twice as long as the first. If the carpenter and his apprentices worked a total of 22 hours, how long did the carpenter work?

Let amount of hours carpenter worked be C 
Then 1st apprentice worked C - 6 hours, and 3rd apprentice worked: 2(C - 6) = 2C - 12 hours
As all 3 worked for a total of 22 hours, we get: C + C - 6 + 2C - 12 = 22
                                                             4C - 18 = 22
                                                                  4C = 40
                             Number of hours carpenter worked, or

Answer by josgarithmetic(39617) About Me  (Show Source):
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Person           TIME
CARPENTER         w
APPTC1            w-6
APPTC2           2(w-6)
Total             22

w%2B%28w-6%29%2B2%28w-6%29=22----solve this.