SOLUTION: I need to know how to solve this problem: Find the equation of the line that contains the point (-3, -8) and is parallel to the line 5x+4y=11. I can get to the point of 5x=11-4y b

Algebra ->  Linear-equations -> SOLUTION: I need to know how to solve this problem: Find the equation of the line that contains the point (-3, -8) and is parallel to the line 5x+4y=11. I can get to the point of 5x=11-4y b      Log On


   

Question 1166384: I need to know how to solve this problem: Find the equation of the line that contains the point (-3, -8) and is parallel to the line 5x+4y=11. I can get to the point of 5x=11-4y but don't know where to go from here. I am not sure what they mean "Write the equation in slope-intercept form if possible" Thank you
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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contains the point (-3, -8) and is parallel to the line 5x+4y=11.
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For parallel, the left side member stays the same; but the right side member is the result of using the values of coordinates in the given point.

5x%2B4y=5%28-3%29%2B4%28-8%29
5x%2B4y=-15-32
highlight%285x%2B4y=-47%29
NOW, if you want the result in slope-intercept form, then SOLVE FOR y IN TERMS OF x AND PUT INTO FORM, y=mx+b.