SOLUTION: Through the point (2,4) and perpendicular to the line whose equation is x-5y+10=0.

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Question 1163819: Through the point (2,4) and perpendicular to the line whose equation is x-5y+10=0.
Found 2 solutions by solver91311, josgarithmetic:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

What about "Through the point (2,4) and perpendicular to the line whose equation is x-5y+10=0."? Ask an actual question, please. Tell us what you are having difficulty understanding and show the work you have done so far to solve the problem, successful or otherwise.

John

My calculator said it, I believe it, that settles it

Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!
Perpendicular to the given equation is and to find this v,
, using the required point;