SOLUTION: Through the point (2,4) and perpendicular to the line whose equation is y-5y+10=0.

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Question 1163818: Through the point (2,4) and perpendicular to the line whose equation is y-5y+10=0.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
A bit unclear. What is that given equation? Both terms variable y? Is one of the terms supposed to have variable x?

Fix it HERE!

The result you are looking for is consistent with 5x%2By-14=0.