Question 1163765: What is an equation of the line which is parallel to 3x+7y=4 and passes
through (5,-2) ? Found 3 solutions by Boreal, Edwin McCravy, MathTherapy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Get the slope of the first line, which is 7y=-3x+4 and y=-(3/7)x+(4/7)
The slope of the line desired is -3/7
point slope formula y-y1=m(x-x1), m slope (x1, y1) point
y+2=(-3/7)*(x-5)
y=-(3/7)x+(15/7)-2
=(-3/7)x+(1/7)
Any line parallel to to the line ax+by=c can have equation ax+by = K, where
K ≠ c
What is an equation of the line which is parallel to 3x+7y = 4 and passes
through (5,-2)
It can have the equation 3x+7y = K where K ≠ 4
To find K, simply substitute x = 5 and y = -2 in
3x+7y = K
3(5)+7(-3) = K
15-21 = K
-16 = K
Answer: 3x+7y = -16
Edwin
