SOLUTION: Line A is perpendicular to Line B. Determine the equation of Line A if it passes through Line B at (5, -1), where Line B is represented by the equation x + 2y = 3.

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Question 1159868: Line A is perpendicular to Line B. Determine
the equation of Line A if it passes through Line B
at (5, -1), where Line B is represented by the
equation x + 2y = 3.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


First, a solution using elementary methods; you should understand it and be able to solve similar problems by this method.

(1) Put the equation of B in slope-intercept form y+=+mx%2Bb to find the slope.
x%2B2y+=+3
2y+=+-x%2B3
y+=+%28-1%2F2%29x%2B3%2F2
The slope is (-1/2).

(2) Find the slope of a line perpendicular to B -- it is the negative reciprocal of the slope of B: +(2/1) = 2

(3) Find the equation of line A knowing it has a slope of 2 and passes through (5,-1).
y+=+mx%2Bb
-1+=+2%285%29%2Bb
-1+=+10%2Bb
b+=+-1-10+=+-11
The equation is y+=+2x-11

A graph of the two lines -- B red, A green....

graph%28400%2C400%2C-12%2C12%2C-12%2C12%2C%28-1%2F2%29x%2B3%2F2%2C2x-11%29

Alternatively, a shortcut using ideas about vectors. This is a quick path to the answer you can use if a formal algebraic solution is not required.

Given line B with equation x%2B2y=3, every line parallel to B will have an equation of the form x%2B2y=c for some constant c; and every line perpendicular to B will have an equation of the form 2x-y=c for some constant c.

Without understanding vectors, what you need to see is that the coefficients of x and y have switched places, and one of them has changed signs. In this example, the coefficients 1 and 2 become 2 and -1.

So the equation of line A is 2x-y=c; and we can determine the constant c knowing that (x,y)=(5,-1) satisfies the equation.

2x-y=c
2%285%29-%28-1%29+=+c
11+=+c

The equation of A is 2x-y+=+11

That is a different form of the same equation found earlier, which was y+=+2x-11