SOLUTION: Given h(x) = −x^2 + 4x − 3 a. h(-3) b. h(x-2) c. h(3a)
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Question 1159613
:
Given h(x) = −x^2 + 4x − 3
a. h(-3)
b. h(x-2)
c. h(3a)
Answer by
josgarithmetic(39617)
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