SOLUTION: Write an equation of the parabola that passes through the point (−10,48) and has x-intercepts −8 and 50. Then find the average rate of change from x=−8 to x=−5

Algebra ->  Linear-equations -> SOLUTION: Write an equation of the parabola that passes through the point (−10,48) and has x-intercepts −8 and 50. Then find the average rate of change from x=−8 to x=−5      Log On


   



Question 1147852: Write an equation of the parabola that passes through the point (−10,48) and has x-intercepts −8 and 50. Then find the average rate of change from x=−8 to x=−5
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

I just found the equation of this parabola under this link

https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.1147818.html

https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.1147818.html


It is f(x) = 0.4*(x+8)*(x-50).


The average rate of change  of this function from x= -8  to  x= -5  is


    r = %28f%28-5%29+-+f%28-8%29%29%2F%28%28-5%29-%28-8%29%29 = %28f%28-5%29-f%28-8%29%29%2F3.


Notice that f(-8) = 0,  so the last formula simplifies to


    r = f%28-5%29%2F3.


You do the rest.