SOLUTION: Rita invested her savings in two investment funds. The amount she invested in Fund A was 3 times as much as the amount she invested in Fund B. Fund A returned a 3% profit and Fund

Algebra ->  Linear-equations -> SOLUTION: Rita invested her savings in two investment funds. The amount she invested in Fund A was 3 times as much as the amount she invested in Fund B. Fund A returned a 3% profit and Fund       Log On


   



Question 1147222: Rita invested her savings in two investment funds. The amount she invested in Fund A was 3 times as much as the amount she invested in Fund B. Fund A returned a 3% profit and Fund B returned a 6% profit. How much did she invest in Fund B, if the total profit from the two funds together was $1350?
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let x be the amount (in dollars) invested in fund B at 6% interest.


Then investment in fund A is 3x dollars, at 3% interest.


Total interest is the sum of partial interests


    0.03*(3x) + 0.06*x = 1350.


Simplify and solve for x


    0.09x + 0.06x = 1350,

    0.15x = 1350,

    x     = 1350%2F0.15 = 9000  dollars.


The amount invested in fund B was $9000.     ANSWER


Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If this is simple interest and it's for 1 year,
fund A
(1) +I+=+P%2Ar%2At+
(1) +I+=+3P%2A.03%2A1+
(1) +I+=+.09P+
-------------------------
fund B
(2) +1350+-+I+=+P%2A.06%2A1+
(2) +1350+-+.09P+=+.06P+
(2) +.15P+=+1350+
(2) +P+=+9000+
She invested $9,000 in fund B
------------------------------------
check:
+I+=+.09P+
+I+=+.09%2A9000+
+I+=+810+
and
(2) +1350+-+I+=+.06P+
(2) +1350+-+810+=+.06P+
(2) +540+=+.06P+
(2) +P+=+9000+
OK