SOLUTION: please help of this 1. Given the function Y=-(x+1)^2+3 a) Find the X- and Y- intercepts (2 points) b) Find the maximum or minimum values (2 points) c) Sketch the funct

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Question 1145566: please help of this
1. Given the function
Y=-(x+1)^2+3

a) Find the X- and Y- intercepts (2 points)
b) Find the maximum or minimum values (2 points)
c) Sketch the function.

Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!
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Y=-(x+1)^2+3
a) Find the X- and Y- intercepts (2 points)
b) Find the maximum or minimum values (2 points)
c) Sketch the function.
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(a)
Let x be 0 and solve for y.
Let y be 0 and solve for x.

(b)
Read from the equation in the form you are given.
Maximum point is (-1, 3).
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(?)----Look at the form of the equation! Certain values in their places tell you the coordinates for the vertex, and that it is a maximum point.
Starting with y=x^2, if change to y=-x^2, this reflects through the x axis at the vertex. Change to y=-(x-h)^2, will move entire graph h units to the right if h is positive. Change to y=-(x-h)^2+k, will move entire graph up by k units if k is positive.

(c)