SOLUTION: Find the slope-intercept form of an equation for the line that passes through (-1,2) and is parallel to y equals 2x-3.

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Question 1144843: Find the slope-intercept form of an equation for the line that passes through (-1,2) and is parallel to y equals 2x-3.
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+%28+y+-+2+%29+%2F+%28+x+-%28-1%29+%29+=+m+
Find +m+
+y+=+m%2Ax+%2B+b+
+y+=+2x+-+3+
+m+=+2+
+%28+y+-+2+%29+%2F+%28+x+-%28-1%29+%29+=+2+
+%28+y+-+2+%29+%2F+%28+x+%2B+1+%29+=+2+
+y+-+2+=+2%2A%28+x+%2B+1+%29+
+y+-+2+=+2x+%2B+2+
+y+=+2x+%2B+4+
-------------------------
check:
Does the line go through ( -1,2 )
+2+=+2%2A%28-1%29+%2B+4+
+2+=+-2+%2B+4+
+2+=+2+
OK

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Find the slope-intercept form of an equation for the line that passes through (-1,2) and is parallel to y equals 2x-3.
Point slope form of a linear equation: matrix%281%2C3%2C+y+-+y%5B1%5D%2C+%22=%22%2C+m%28x+-+x%5B1%5D%29%29
As the lines are parallel, their slopes are equal, so required equation will have slope, or m = 2
y - 2 = 2(x - - 1) ------ Substituting 2 for m (slope), and point (x, y) or (- 1, 2) in point slope form of a linear equation
y - 2 = 2(x + 1)
y - 2 = 2x + 2
highlight_green%28matrix%281%2C3%2C+y%2C+%22=%22%2C+2x+%2B+4%29%29