SOLUTION: The amount of copper ore produced from a copper mine in Arizona is modeled by the function f(t)=200+32t, where t is the numbers of years since 2005 and f(t) is measured in thousand
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-> SOLUTION: The amount of copper ore produced from a copper mine in Arizona is modeled by the function f(t)=200+32t, where t is the numbers of years since 2005 and f(t) is measured in thousand
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Question 1136210: The amount of copper ore produced from a copper mine in Arizona is modeled by the function f(t)=200+32t, where t is the numbers of years since 2005 and f(t) is measured in thousands of tons.
A. What is the slope of the graph? P.S I think maybe it is 32 but I'm not sure
B. At what rate is the amount of ore produced changing?(Be specfic include units)
C. How much ore had been mined by the year 2005?(Be specfic include units) Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! All the units in the equation have to be consistent, so
the terms must look like:
[ thousands of tons ] = [ thousands of tons ] + [ thousands of tons ]
The constant term just shifts the graph up or down ( up in this case )
and has no effect on the slope
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(a)
The units of the are broken down like this:
[ thousands of tons ] = [ ( thousands of tons / year ) x ( years ) ]
This is [ slope ] x [ time ], so the slope is
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(b)
32 thousand tons / year
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The year 2005 is on the graph, so
200 thousand tons were mined by 2005
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Here's the graph:
