SOLUTION: Please help me to write an equation for the line perpendicular to y = 3x - 5 that contains (-2,-3).

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Question 1131508: Please help me to write an equation for the line perpendicular to y = 3x - 5 that contains (-2,-3).
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
write an equation for the line perpendicular to y = 3x - 5 that contains (-2,-3).
the relationship of the slopes of perpendicular lines m1 * m2 = -1
In this case m1 = 3, find the slope of the perpendicular line
3m = -1
m = -1%2F3
:
Using the point slope form y - y1 = m(x-x1),
x1=-2; y1=-3; m=-1%2F3
y -(-3) = -1%2F3(x -(-2))
minus a minus is a plus
y + 3 = -1%2F3(x + 2)
y + 3 = -1%2F3x - 2%2F3
y = -1%2F3x - 2%2F3 - 3
y = -1%2F3x - 2%2F3 - 9%2F3
y = -1%2F3x - 11%2F3 is the equation
:
looks like this
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+3x-5%2C+%28-1%2F3%29x-%2811%2F3%29%29+
note the green intersects at -2,-3