SOLUTION: Wayne invested $9000, part at 9%/annum and the remainder at 8%/annum. After one year the total interest from these investments was $750. How much was invested at 9%?

Algebra ->  Linear-equations -> SOLUTION: Wayne invested $9000, part at 9%/annum and the remainder at 8%/annum. After one year the total interest from these investments was $750. How much was invested at 9%?      Log On


   

Question 1124281: Wayne invested $9000, part at 9%/annum and the remainder at 8%/annum. After one year the total
interest from these investments was $750. How much was invested at 9%?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
0.09*x + 0.08*(9000-x) = 750,


0.09x + 0.08*9000 - 0.08x = 750


(0.09 - 0.08)*x = 750 - 0.08*9000


x = %28750+-+0.08%2A9000%29%2F%280.09+-+0.08%29 = 3000.


Answer.  $3000 was invested at 9%.