|
Question 1123230: How to write an equation of the line containing the specified point and parallel to the indicated line (-1,-6)2, x-5y=1
Found 3 solutions by solver91311, Alan3354, ikleyn: Answer by solver91311(24713) (Show Source): Answer by Alan3354(69443) (Show Source): Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
How to write an equation of the line containing the specified point and parallel to the indicated line (-1,-6) , x-5y=1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
First, pay attention on how I edited your post, deleting unnecessary element.
Correctly formulated Math problem, like ancient Greek statues, should not contain unnecessary elements.
Now, a parallel line to the given line has equation
x- 5y = c. (*)
In this equation, the left side IS THE SAME as in the given equation.
The right side "c" is the constant term. It has its own value for each parallel line and it specifies each parallel line by a unique way.
You will find the value of "c" by using the condition that the given point (-1,-6) lies on this line,
i.e. satisfies the equation (*). For it, you simply substitute the coordinates x= -1 and y= -6 into equation (*) and calculate "c" :
(-1) - 5*(-6) = -1 + 30 = 29.
So, c= 29, and the equation you are looking for is
x - 5y = 29.
Solved.
-----------------
To learn more on this subject, look into the lesson
- Equation for a straight line parallel to a given line and passing through a given point
in this site.
|
|
|
| |