SOLUTION: How many gallons of a 90​% antifreeze solution must be mixed with 60 gallons of 20​% antifreeze to get a mixture that is 80​% ​antifreeze?
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-> SOLUTION: How many gallons of a 90​% antifreeze solution must be mixed with 60 gallons of 20​% antifreeze to get a mixture that is 80​% ​antifreeze?
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Question 1122587: How many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 20% antifreeze to get a mixture that is 80% antifreeze? Answer by ikleyn(52781) (Show Source):
Your equation is
pure antifreeze + pure antifreeze = total pure antifreeze
0.9x + 0.2*60 = 0.8(x+60).
Solve for x, which is the number under the question.
