SOLUTION: If Don Has 2 More Than 3 Times The Number Of Marbles Mark Has,how Many Does Each Boy Have To Sell If The Total Number Of Marbles Is 98

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Question 1122301: If Don Has 2 More Than 3 Times The Number Of Marbles Mark Has,how Many Does Each Boy Have To Sell If The Total Number Of Marbles Is 98
Found 3 solutions by josgarithmetic, Boreal, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Don: 3m+2 marbles
Mark: m
Total: 98

3m%2B2%2Bm=98

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
D+M=98, where D=Don's marbles and M=Mark's marbles
D=3M+2
therefore, 3M+2+M=98
4M=96
M=24 ANSWER
D=74, three times M plus 2. ANSWER

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Mark + Don      = 98


M    + (3M + 2) = 98


M    + 3M + 2   = 98


4M = 98 - 2 = 96   ====>  M = 96%2F4 = 24.


Answer.  Mark has 24  and  Don has 98 - 24 = 74.

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