SOLUTION: Find the equation of the lines that are both passing through the point (10,-8) with slopes 5 and -1/5. Answer: ___ x - y - ____ = 0 x + ___ y+ ____ = 0

Algebra ->  Linear-equations -> SOLUTION: Find the equation of the lines that are both passing through the point (10,-8) with slopes 5 and -1/5. Answer: ___ x - y - ____ = 0 x + ___ y+ ____ = 0      Log On


   

Question 1120391: Find the equation of the lines that are both passing through the point (10,-8) with slopes 5 and -1/5.
Answer: ___ x - y - ____ = 0
x + ___ y+ ____ = 0
Found 2 solutions by josgarithmetic, Theo:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the equation of the lines that are both passing through the point (10,-8) with slopes 5 and -1/5.
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system%28%28y%2B8%29%2F%28x-10%29=5%2Cand%2C%28y%2B8%29%2F%28x-10%29=-1%2F5%29

Do what you need to put the system into the form you want.

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
both lines pass through the point (10,-8).
slope of the first line is 5.
slope of the second line is -1/5.

use the point slope form of the equation to solve this.

point slope form is (y-y1) = m * (x-x1)
m is the slope
y1 is the y-coordinate of the point.
x1 is the x-coordinate of the point.

(y-y1) = m * (x-x1) becomes y+8 = 5 * (x-10)

simplify to get y + 8 = 5x - 50

subtract 5x from both sides of this equation and subtract 8 from both sides of this equation to get:

y - 5x = -50 - 8

simplify to get:

y - 5x = -58

multiply both sides of this equation by -1 to get:

-y + 5x = 58

place the x variable ahead of the y variable to get:

5x - y = 58

subtract 58 from both sides of the equation to get:

5x - y - 58 = 0

your solution is 5x - y - 58 = 0