SOLUTION: A shopkeeper sells a eraser for RS 2 and a shapner at rs 3 .ram purchases some erasers and sharpners.while calculating the amount mistakenly he considers rs 3 for eraser and 2 for
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-> SOLUTION: A shopkeeper sells a eraser for RS 2 and a shapner at rs 3 .ram purchases some erasers and sharpners.while calculating the amount mistakenly he considers rs 3 for eraser and 2 for
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Question 1118987: A shopkeeper sells a eraser for RS 2 and a shapner at rs 3 .ram purchases some erasers and sharpners.while calculating the amount mistakenly he considers rs 3 for eraser and 2 for sharpener. The amount is 10 rupees more than the actual amount.find the number of sharpner purchased if ram purchases 20 item in all Answer by ikleyn(52781) (Show Source):
Let X be the number of sharpeners Ram purchased.
Then the number of erasers was (20-X).
The correct cost of his purchase was 3*X + 2*(20-X) rupees.
The mistakenly calculated cost was 2X + 3*(20-X).
The difference between these two values is 10 rupees, which gives you an equation
2X + 3*(20-X) = 3x + 2*(20-X) + 10.
Simplify and solve for X:
2X + 60 - 3X = 3X + 40 - 2X + 10
60 - 40 - 10 = 3X - 2X - 2X + 3X
10 = 2X
X = = 5.
Answer. The number of sharpeners was 5.
