SOLUTION: Two factory plants are making TV panels. Yesterday, Plant A produced 16,000 panels. Three percent of the panels from Plant A and 10% of the panels from Plant B were defective.

Algebra ->  Linear-equations -> SOLUTION: Two factory plants are making TV panels. Yesterday, Plant A produced 16,000 panels. Three percent of the panels from Plant A and 10% of the panels from Plant B were defective.       Log On


   

Question 1109959: Two factory plants are making TV panels. Yesterday, Plant A produced 16,000
panels. Three percent of the panels from Plant A and 10%
of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from
two plants was 6%
?

Answer by ikleyn(52920) About Me  (Show Source):
You can put this solution on YOUR website!
.
0.03*16000 + 0.1*b = 0.06*(16000+b)    (counting defective panels)  ====>


480 + 0.1b = 0.06*16000 + 0.06*b

480 + 0.1b = 960 + 0.06*b

0.1b - 0.06b = 960 - 480  

0.04b = 480  ====>  b = 480%2F0.04 = 12000.


Answer.  Plant B produces 12000 panels.


Check.  0.03*16000 + 0.1*12000 = 1680;  0.06*(16000+12000) = 1680.   ! Correct !

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