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I need help with the question OF HOW TO FIND THE EQUATION FOR THE LINE through (4,-4), parallel to y=-x-4.
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Using the point-slope form, if you want, slope needed for "parallel", is , as from .
In the given equation, y = -x-4 (or y = -1x-4), the -1 is the slope of the line.
Any line parallel to the given line will have the same slope; so it will have an equation of the form y = -x+k, where k is some constant.
If you know the coordinates of a point that the new line passes through, you can determine the value of k by using those coordinates in the general form of the equation:
The required constant, to have the line pass through (4,-4), is 0; so the equation of the line is y = -x+0, or just y = -x.