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Question 110860This question is from textbook
: Find the x and y-intercepts, if they exist. y= 8x
This question is from textbook
Found 2 solutions by scott8148, bucky:
Answer by scott8148(6628)   (Show Source):
Answer by bucky(2189)  (Show Source):
You can put this solution on YOUR website! To find the intercept on the y-axis let x = 0. [This is because any point on the y-axis has zero
as its x value.]
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If you go to the given equation:
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y = 8x
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and substitute 0 for x, the equation becomes:
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y = 8*0 = 0
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This tells you that when x = 0, then y = 0 and the point is (0, 0). So the y-intercept
for the given equation is the origin.
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At this point in the problem, you can tell that the x-intercept is also (0, 0) if you
really think about it. However, the routine way to find the x-intercept is to set y equal
to zero in the equation. If you do, the equation becomes:
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0 = 8*x
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Solve for x by dividing both sides by 8 to get:
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0/8 = 0 = x
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So the point (0, 0) is also the x-axis intercept.
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Hope this helps you to understand the problem.
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