SOLUTION: The hare challenged the tortoise to a race from the water fountain to the park bench. In order to ensure a fair race, the tortoise will start 100 feet in front of the hare. The tor

Algebra ->  Linear-equations -> SOLUTION: The hare challenged the tortoise to a race from the water fountain to the park bench. In order to ensure a fair race, the tortoise will start 100 feet in front of the hare. The tor      Log On


   

Question 1107394: The hare challenged the tortoise to a race from the water fountain to the park bench. In order to ensure a fair race, the tortoise will start 100 feet in front of the hare. The tortoise is walking at a rate of 2 feet per minute. The hare is walking at a rate of 6 feet per minute.
A. How long will it take for the hare to catch up to the tortoise?
B. How long did the hare wait before walking (in order for the tortoise to walk 100 feet)?
C. The distance from the water fountain to the park bench is 130 feet. Who won the race?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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The hare challenged the tortoise to a race from the water fountain to the park bench.
In order to ensure a fair race, the tortoise will start 100 feet in front of the hare.
The tortoise is walking at a rate of 2 feet per minute.
The hare is walking at a rate of 6 feet per minute.
:
A. How long will it take for the hare to catch up to the tortoise?
The relative speed between the tortoise & hare: 6 - 2 = 4 ft/min
Find how long for the hare to travel 100 ft at this speed
t = 100/4
t = 25 min
:
B. How long did the hare wait before walking (in order for the tortoise to walk 100 feet)?
t = 100/2
t = 50 min wait for the tortoise to be 100 ft away
:
C. The distance from the water fountain to the park bench is 130 feet.
Who won the race?
The tortoise will travel 30 ft while the hare must travel 130 ft
find the time of each
t = 30/2
t = 15 min for the tortoise
and
t = 130/6
t = 212%2F3 min for the hare to reach the fountain, he loses.