SOLUTION: In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate receive? I need to show the equatio

Algebra ->  Linear-equations -> SOLUTION: In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate receive? I need to show the equatio      Log On


   

Question 110227: In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate receive?
I need to show the equation, thanks!

Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate receive?
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Let the number of loser votes be "x"
The number of winner votes is "x+220"
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EQUATION:
loser votes + winner votes = 810
x + x+220 = 810
2x +220 = 810
2x = 590
x = 295 (# of loser votes)
x+220 = 515 (# of winner votes)

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the winning candidate ( let him be x) had 220 more votes than the loser (let him be y)
x+=+y+%2B+220
If 810 votes were cast in all, then
810+=+x+%2B+y
810+=+y+%2B+220+%2B+y
810+=+2y+%2B+220+....move 220 to the left
810+-+220+=+2y
590+=+2y
+y+=+295...........votes that loser did receive

x+=+y+%2B+220
x+=+295+%2B+220
x+=+515...........votes that winning candidate did receive
check:
810+=+x+%2B+y
810+=+515+%2B+295
810+=+810