SOLUTION: Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2. (write the numerical coefficient of each term to complete the required equation

Algebra ->  Linear-equations -> SOLUTION: Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2. (write the numerical coefficient of each term to complete the required equation      Log On


   

Question 1099788: Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2. (write the numerical coefficient of each term to complete the required equation
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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...perpendicular to the line 3y-7x=2, ...
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7x%2B3y=C


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... goes through the point (2,-5),...
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7x%2B3y=7%2A2%2B3%2A%28-5%29

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2.
(write the numerical coefficient of each term to complete the required equation
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The given line 3y - 7x = 2  is  y = %287x+%2B+2%29%2F3  and has the slope 7%2F3.


Hence, the perpendicular line has the slope  -3%2F7, which is reciprocal with the opposite sign.


The the equation of this perpendicular line passing through the point (2,-5) is 

y - (-5) = %28-3%2F7%29%2A%28x-2%29.


Multiply both sides by 7.  You will get

7y + 35 = -3(x-2),   or   7y + 35 = -3x + 6,   or finally

3x + 7y = -29.




The line 3y - 7x = 2 (original line, red) and the line 3x + 7y = -29 (perpendicular passing through (2,-5), green)

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The solution by @josgarithmetic is W R O N G. Simply ignore it.