SOLUTION: Represent in the form of coordinates (x,y) the solution to this system of linear equations: 3x + 2y = 48 6x + 6y = 64

Algebra ->  Linear-equations -> SOLUTION: Represent in the form of coordinates (x,y) the solution to this system of linear equations: 3x + 2y = 48 6x + 6y = 64      Log On


   

Question 1099540: Represent in the form of coordinates (x,y) the solution to this system of linear equations: 3x + 2y = 48 6x + 6y = 64
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
3x + 2y = 48 6x + 6y = 64
?

system%283x%2B2y=48%2C+6x%2B6y=64%29

system%283x%2B2y=48%2C3x%2B3y=32%29

Subtract first equation from the second equation.
y=32-48
y=-16


3x=48-2y
3x=48-2%28-16%29
3x=48%2B32
3x=80
x=80%2F3=26%262%2F3

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( 26&2/3, -16 )
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Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Represent in the form of coordinates (x,y) the solution to this system of linear equations: 3x + 2y = 48 6x + 6y = 64
FYI: 

IGNORE all such answers!

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
3x + 2y = 48,   (1)
6x + 6y = 64.   (2)


Divide eq(2) by 2 (both sides).  You will get the modified system

3x + 2y = 48,   (1')
3x + 3y = 32.   (2')


Subtract eq(1) from eq(2)  (both sides).  You will get

y = 32 - 48 = -16.


Thus you just found the solution for y.

Now substitute it into either equation (1) or (2). I will substitute into eq(1). You will get

3x + 2*(-16) = 48  ====>  3x = 48 + 32 = 80  ====>  x = 80%2F3.


Answer.  The solution is (x,y) = (80%2F3,-16).