SOLUTION: Find the value of k so that the line containing the points (-1,-5) and (-3,k) is perpendicular to the line containing the points (-7,-1) and (0,-7).

Algebra ->  Linear-equations -> SOLUTION: Find the value of k so that the line containing the points (-1,-5) and (-3,k) is perpendicular to the line containing the points (-7,-1) and (0,-7).      Log On


   

Question 1095806: Find the value of k so that the line containing the points (-1,-5) and (-3,k) is perpendicular to the line containing the points (-7,-1) and (0,-7).
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Slope of first pair: %28k%2B5%29%2F%28-2%29

Slope of second pair: -6%2F7

Lines to be perpendicular means product of slopes -1.
%28-%28k%2B5%29%2F2%29%28-6%2F7%29=-1
%28%28k%2B5%29%2F2%29%286%2F7%29=-1
3%28k%2B5%29%2F7=-1
3k%2B15=-7
3k=-7-15=-22
k=-22%2F3
highlight%28k=-7%261%2F3%29
(still need to be rechecked)



Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the value of k so that the line containing the points (-1,-5) and (-3,k) is perpendicular to the line containing the points (-7,-1) and (0,-7).
Correct answer: highlight_green%28matrix%281%2C3%2C+k%2C+%22=%22%2C+-+7%261%2F3%29%29

IGNORE anyone who says otherwise.