SOLUTION: Given the circle X^2+y^2=25 in the first quadrant, find the equation of the tangent line at x=3

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Question 1093544: Given the circle X^2+y^2=25 in the first quadrant, find the equation of the tangent line at x=3
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Given the circle X^2+y^2=25 in the first quadrant, find the equation of the tangent line at x=3
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At x = 3, y = 4
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Slope of the line thru the Origin to (3,4) = 4/3
Tangent line is perpendicular to the radial line.
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Slope of tangent line = -x/y = -3/4
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y-4 = (-3/4)*(x-3)