SOLUTION: {{{V=-2.6+d/3}}} The electric potential, {{{V}}}, in volts, between two metal plates a distance of {{{d}}} millimetres from the left plate is given by the equation above when 0&

Algebra ->  Linear-equations -> SOLUTION: {{{V=-2.6+d/3}}} The electric potential, {{{V}}}, in volts, between two metal plates a distance of {{{d}}} millimetres from the left plate is given by the equation above when 0&      Log On


   

Question 1090858: V=-2.6%2Bd%2F3
The electric potential, V, in volts, between two metal plates a distance of d millimetres from the left plate is given by the equation above when 0≤d≤15. By how many millimetres does the distance from the left plate increase for the potential to increase by 1 volt?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Solve the equation for d
V=-2.6%2Bd%2F3
V%2B2.6=d%2F3
3%28V%2B2.6%29=d
d=3V%2B3%282.6%29
d=3V%2B7.8
This is a linear function with m = 3 being the slope.
The slope of 3 means that for every unit increase of V, the value of d will increment by 3.

Therefore the final answer is 3

Note: the domain of the equation d=3V%2B7.8 is -2.6+%3C=+V+%3C=+2.4 because of two facts
Fact 1: Plugging d = 0 into the original equation V=-2.6%2Bd%2F3 leads to V = -2.6
Fact 2: Plugging d = 15 into the original equation V=-2.6%2Bd%2F3 leads to V = 2.4