SOLUTION: parallel lines, perpendicular lines, or neither 12x+4y=16 18x+6y=26 y=3x-4 9x+3y=8

Algebra ->  Linear-equations -> SOLUTION: parallel lines, perpendicular lines, or neither 12x+4y=16 18x+6y=26 y=3x-4 9x+3y=8      Log On


   



Question 1088774: parallel lines, perpendicular lines, or neither
12x+4y=16
18x+6y=26
y=3x-4
9x+3y=8

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Get all the slopes
the first is 4y=-12x+16 and the slope is -3, after dividing by 4 to make 1y on the left.
similar, the second will have a slope of -3 as well, so the first two are parallel
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The third one has slope 3 and is not parallel or perpendicular to the first two. It ranks neither. One needs a slope of +1/3 to make it perpendicular.
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The fourth becomes 3y=-9x+8 or y=(-3x)+(8/3), and that is parallel to the two top ones.