SOLUTION: Write the equation for the line (in y=mx + b form) that is perpindicular to the line with equation y= -4/3x -4 that passes through the point (-5,6)

Algebra ->  Linear-equations -> SOLUTION: Write the equation for the line (in y=mx + b form) that is perpindicular to the line with equation y= -4/3x -4 that passes through the point (-5,6)      Log On


   

Question 1087474: Write the equation for the line (in y=mx + b form) that is perpindicular to the line with equation y= -4/3x -4 that passes through the point (-5,6)
Found 2 solutions by MathLover1, Boreal:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
y=mx+%2B+b
if the line that is perpendicular to the line with equation
+y=+-%284%2F3%29x+-4 and this line has a slope m=-%284%2F3%29, then perpendicular line will have a slope m%5Bp%5D=-1%2F%28-4%2F3%29=3%2F4
so far your equation is:
y=%283%2F4%29x+%2B+b ....now use given point (-5,6) to find b
6=%283%2F4%29%28-5%29+%2B+b
6=-15%2F4+%2B+b
6%2B15%2F4+=+b
39%2F4+=+b
and,your equation is:
y=%283%2F4%29x+%2B+39%2F4




Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
the slopes of perpendicular lines have a negative reciprocal product, or -1.
the slope of the other line is 3/4
y-y1=m(x-x1), m slope, (x1,y1) point
(y-6)=(3/4)(x+5)
y=(3/4)x+(39/4)
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-4x%2F3%29-4%2C%283x%2F4%29%2B%2839%2F4%29%29