SOLUTION: y=mx+b My answer choices are the following: A) m>0 b<0 B) m<0 b>0 C) m>0 b>0 D) m<0 b<0 knowing that both m and b are 0, How can I determine whether the signs would be gr

Algebra ->  Linear-equations -> SOLUTION: y=mx+b My answer choices are the following: A) m>0 b<0 B) m<0 b>0 C) m>0 b>0 D) m<0 b<0 knowing that both m and b are 0, How can I determine whether the signs would be gr      Log On


   



Question 1087168: y=mx+b
My answer choices are the following:
A) m>0 b<0
B) m<0 b>0
C) m>0 b>0
D) m<0 b<0
knowing that both m and b are 0, How can I determine whether the signs would be greater or less than? Here is a picture of the graph: http://postimg.org/image/9yewucj97/

Found 2 solutions by rothauserc, MathTherapy:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
Is this a straight line going through the origin?
:
does it really look like this?
:
+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+-x%29+
:

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!

y=mx+b
My answer choices are the following:
A) m>0 b<0
B) m<0 b>0
C) m>0 b>0
D) m<0 b<0
knowing that both m and b are 0, How can I determine whether the signs would be greater or less than? Here is a picture of the graph: http://postimg.org/image/9yewucj97/
The equation of the graph is: y = - x
From that, you can see that m, or slope < 0, and b (y-intercept) = 0.