SOLUTION: suppose 15 quarts of a solution that is 35% antifreeze is mixed with 5 quarts of a solution that is 72% antifreeze A)How many quarts of antifreeze are in the resulting mixture?

Algebra ->  Linear-equations -> SOLUTION: suppose 15 quarts of a solution that is 35% antifreeze is mixed with 5 quarts of a solution that is 72% antifreeze A)How many quarts of antifreeze are in the resulting mixture?       Log On


   

Question 1085714: suppose 15 quarts of a solution that is 35% antifreeze is mixed with 5 quarts of a solution that is 72% antifreeze
A)How many quarts of antifreeze are in the resulting mixture?
B)what percentage of the resulting mixture is antifreeze?
Found 2 solutions by josmiceli, jorel1380:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+.35%2A15+=+5.25+ quarts of antifreeze
+.72%2A5+=+3.6+ quarts of antifreeze
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A)
+5.25+%2B+3.6+=+8.85+
There are 8.85 quarts of antifreeze in the
resulting mixture
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B)
+15+%2B+5+=+20+ total quarts of mixture
+8.85%2F20+=+.4425+
+.4425%2A100+=+44.25+
The % of the resulting mixture that is antifreeze
is 44.25%



Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
a.15x.35=5.25
5 x 0.72=3.6
Total:5.25+3.6=8.85 qts. antifreeze
b. 8.85/15+5=.4425, or 44.25% antifreeze. ☺☺☺☺