SOLUTION: Find the equation given the endpoints of the diameter (5,2) (1,-2).

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Question 1081949: Find the equation given the endpoints of the diameter (5,2) (1,-2).
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!

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Center at midpoint of the diameter
%285%2B1%29%2F2=3
%282%2B%28-2%29%29%2F2=0
(3,0)

Radius-squared
%285-3%29%5E2%2B%282-0%29%5E2
4%2B4
8




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%28x-3%29%5E2%2By%5E2=8

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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The center is at he point (3,0).


The radius length is sqrt%28%285-3%29%5E2+%2B+2%5E2%29 = sqrt%282%5E2%2B2%5E2%29 = sqrt%288%29.


The equation of the circle is

%28X-3%29%5E2+%2B+y%5E2 = 8.