|
Question 1079202: 2 perpendicular lines intersect on the x axis. One of the lines is 2x-y +3=0 find the equation of the second line. Write your answer in general form
Found 2 solutions by josmiceli, ikleyn: Answer by josmiceli(19441) (Show Source): Answer by ikleyn(52824) (Show Source):
You can put this solution on YOUR website! .
For the given line, the x-intercept is x = (it makes y = 0).
So, we need to find the equation of the line perpendicular to the given line and passing through the point (-1.5,0).
The given line has the slope 2 (because the equation of the given line in the slope-form is y = 2x+3).
Hence, the slope of the perpendicular line is -0.5.
The straight line with the slope -0.5 through the point (-1.5,0) is
y - 0 = (-0.5)*(x-(-1.5)), or
y = -0.5*(x+1.5).
It is the same as
2y = -(x+1.5), or
4y = - 2x - 3, or
2x + 4y + 3 = 0,
on your choice.
Solved. And plotted:
Plot y = 2x+3 (red) and y = -0.5*(x+1.5) (green)
|
|
|
| |