SOLUTION: Write the equation of the line which passes through the point (2, 1) and is parallel to the line with equation y = 5/2 x + 6 (that is five over 2 with an x next to the fraction).

Algebra ->  Linear-equations -> SOLUTION: Write the equation of the line which passes through the point (2, 1) and is parallel to the line with equation y = 5/2 x + 6 (that is five over 2 with an x next to the fraction).      Log On


   

Question 107801: Write the equation of the line which passes through the point (2, 1) and is parallel to the line with equation y = 5/2 x + 6 (that is five over 2 with an x next to the fraction).
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Y=5X/2+6 HAS A SLOPE OF 5/2 (RED LINE)
SO A PARALLEL LINE ALSO HAS A SLOPE OF 5/2.
NOW SUBSTITUTE THE (2,1) VALKUES FOR (X,Y) IN THE STANDARD LINE FORMULA & SOLVE FOR THE Y INTERCEPT THUS:
1=5/2*2+b
1=5+b
b=1-5
b=-4 THE Y INTERCEPT.
THUS THE LINE EQUATION IS:
Y=5X/2-4 ANSWER. (GREEN LINE)
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+5x%2F2+%2B6%2C+y+=+5x%2F2+-4%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions y = 5x/2 +6 and y = 5x/2 -4).